Skip to main content

To check if given string is palindrome or not.

To check if given string is palindrome or
not.






#include <stdio.h>
#include <string.h>
#include<conio.h>
 

int main()
 

{
 

char a[100], b[100];

printf("Enter the string to check if it is a palindrome\n");
 

gets(a);
 

strcpy(b,a);
 

strrev(b);
 

if( strcmp(a,b) == 0 )
 

printf("Entered string is a palindrome.\n");
 

else
 

printf("Entered string is not a palindrome.\n");
 

return 0;
 

}




Comments

Popular posts from this blog

To Check Whether a Number is Even or Odd

C Program to Check Whether a Number is Even or Odd Numbers perfectly divisible by 2 are known even numbers and numbers which are not divisible by 2 are called odd numbers. This program takes an integer from user and checks whether that number is even or odd and displays the result. Source Code /*to check whether a number entered by user is even or odd. */ #include <stdio.h> int main() { int num; printf( "Enter an integer you want to check: " ); scanf( "%d" ,&num); if ((num% 2 )== 0 ) /* Checking whether remainder is 0 or not. */ printf( "%d is even." ,num); else printf( "%d is odd." ,num); return 0 ; } Output 1 Enter an integer you want to check : 25 25 is odd . Output 2 Enter an integer you want to check : 12 12 is even .   In this program, user is asked to enter an integer which is stored in variable num . Then,...

Convert numbers to roman numerals

Convert numbers to roman numerals       #include <stdio.h> #include <conio.h> void predigits (char c1,char c2); void postdigits (char c,int n); char roman_Number[1000]; int i=0; int main() {     int j;     long int number;        printf( "Enter any natural number: " );     scanf( "%d" ,&number);        if (number <= 0) {          printf("Invalid number");          return 0;     }     while (number != 0){          if (number >= 1000){              postdigits('M',number/1000);              number = number - (number/1000) * 1000;          } ...

C Program to print the pattern

C Program to print the pattern X X Y X Y Z ........................................................................................ #include<stdio.h> #include<conio.h> void main () { int i , j ; for ( i= 88 ; i< 91 ;i ++) { for ( j = 88 ;j <= i ; j ++) { printf ( "%c" , j );                    }           printf ( "\n" ); } getch (); } ........................................................................................ OUTPUT